#63 Bears to Face #18 Notre Dame in NCAA First Round
May 3, 2006
PROVIDENCE, RI - The 63rd ranked Brown men's tennis team (20-9) will travel to Texas A&M, the 16th seed in the tournament, for an NCAA First Round match-up against #18 Notre Dame the weekend of May 12th. The winner of the Brown-Notre Dame match will face the winner of the Texas A&M-Texas Arlington match in the second round. Brown, which shared the 2006 Ivy League Championship with Penn, earned the League's automatic berth by virtue of its 4-3 playoff victory over the Quakers. This marks the second straight year, and the fourth time in the past five years, that Brown will play in the NCAA Tournament.
Brown made its first-ever appearance in the NCAA Tournament in 2002, earning an automatic berth as the Ivy League Champion, and fell to The University of Mississippi, the seventh ranked team in the country, 4-0. The following year, Brown received an at large bid into the tournament, and fell to Wake Forest, the 28th-ranked team in the country, 4-3. Last year, Brown was eliminated in the first round by #26 Ohio State, 4-0.
The 64-team field is broken into 16 first and second round sites. The First and second round matches will take place either Friday-Saturday, May 12-13, or Saturday-Sunday, May 13-14, with the winner of each site advancing to the NCAA Division I Men's Tennis Championships at the Taube Tennis Center in Stanford, California, hosted by the Stanford University. The team championship will be held May 20-23.
The teams will play a single-elimination tournament at 16 first and secondround sites (four teams at each site) and the finals site (16-team bracket) to determine the national champion. The matches shall be regulation dual matches with three eight-game, pro-set doubles played for one team point, followed by six singles matches, each valued at one team point, played best of three sets. Regular scoring will be used and a 12-point tiebreaker will be played at eight games all in doubles and at six games all in singles.